When you graph this, the graph of the function will be symmetric in respect to the y- axis. If f (x)!=f (-x), you could check whether f (-x) equals -f (x). If it does, than the function is odd. If it …

The domain for this function is (0, oo). If an interval I is contained in the domain of this function, it must be a subset of (0, oo) (that is, I sube (0, oo)). The most common things to look at when …

dy/dx = (2x)/5 * 5((x^2+4)/5)^4 = 2x((x^2+4)/5)^4 We can most easily do this via the Chain Rule. The Chain Rule states that, given a function composition f(g(x)), (df ...

The simplest way of looking at lim_ (x->0^+) 1/x is to graph the function: graph {1/x [-10, 10, -5, 5]} We can see that approaching from above zero, the function rarr oo Hence, we have: oolim_ (x …

Yes. See explanation. The period of cot(x) is pi so any integer multiple of pi will not impact the value of the function, so: cot(-t-5pi) = cot(-t). Cotangent is an odd function, so we know that: …

The only function whose domain does not include #1# is the rational function. So that must get number #1#.

In the second interval, the first is positive and the second is negative or zero and the function becomes: y=x+2+x+1rArry=2x+3 a segment. In the third both arguments are positive or zero …

Please see below. . If, by intervals, you mean the period of the function we can find it as follows: 2sin^2(4x)-1=0 We know there is an identity that says: sin^2theta=(1-cos2theta)/2 Using this …

y=-2(x+1)^2+32 or y=-2x^2-4x+30 Given - Quadratic function's Axis of symmetry x=-1 X-intercept x=3 Maximum value of y = 32 [maximum value of the function. Key to this problem If we …

We can't, because that is not the limit. If you intended to write lim_(x->10) 3-(4x)/5 = -5, then see explanation below. One of the first steps in checking the limit of a function at an x-value is …